United States presidential election in Ohio, 1836

United States presidential election in Ohio, 1836
Ohio
November 3 – December 7, 1836

 
Nominee William Henry Harrison Martin Van Buren
Party Whig Democratic
Home state Ohio New York
Running mate Francis Granger Richard Johnson
Electoral vote 21 0
Popular vote 104,958 96,238
Percentage 51.87% 47.56%

President before election

Andrew Jackson
Democratic

Elected President

Martin Van Buren
Democratic

The 1836 United States presidential election in Ohio took place between November 3 and December 7, 1836, as part of the 1836 United States presidential election. Voters chose twenty-one representatives, or electors to the Electoral College, who voted for President and Vice President.

Ohio voted for Whig candidate William Henry Harrison over Democratic candidate Martin Van Buren. Harrison won Ohio by a margin of 4.31%.

Results

United States presidential election in Ohio, 1836[1]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Whig William Henry Harrison of Ohio Francis Granger of New York 104,958 51.87% 21 100.00%
Democratic Martin Van Buren of New York Richard M. Johnson of Kentucky 96,238 47.56% 0 0.00%
N/A Others Others 1,137 0.56% 0 0.00%
Total 202,333 100.00% 21 100.00%

References

  1. "1836 Presidential General Election Results - Ohio". U.S. Election Atlas. Retrieved 23 December 2013.
This article is issued from Wikipedia - version of the 9/9/2016. The text is available under the Creative Commons Attribution/Share Alike but additional terms may apply for the media files.