United States presidential election in Georgia, 1964
The 1964 United States presidential election in Georgia took place on November 3, 1964 throughout all 50 states and D.C., which was part of the 1964 United States presidential election. Voters chose 12 representatives, or electors to the Electoral College, who voted for President and Vice President.
Georgia was won by Senator Barry Goldwater (R-AZ) by an 8.25 percentage point margin of victory.[1] Goldwater's victory in Georgia in 1964 was the Republican party's first ever victory in the state in any Presidential election. This was an incredible feat for Republicans, albeit that Goldwater lost to Lyndon B. Johnson in a landslide that year, considering that the Peach state had long been a Democratic stronghold, which it would remain, Presidential elections aside, well until the 1990s. Between 1852 to 1960, Georgia had supported the Democratic Presidential nominee in every election (with the sole exception of 1864, due to Georgia's secession from the union). However, from this election onward, the Peach state has supported Democrats only three times since (two of those were when Georgia native Jimmy Carter was on the ballot).
During the Concurrent House elections of 1964 in Georgia, Republicans picked up a seat from the Democrats, that being the Third district House seat won by Howard Callaway who became the first Republican to be elected to the House of Representatives from Georgia since Reconstruction.
Results
(*The Constitution Party of the 1950s-60s should not be confused the modern Constitution Party)
References
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