United States presidential election in Missouri, 1828
Main article: United States presidential election, 1828
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Elections in Missouri | ||||||||||||||||
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The 1828 United States presidential election in Missouri took place between October 31 and December 2, 1828, as part of the 1828 United States presidential election. Voters chose three representatives, or electors to the Electoral College, who voted for President and Vice President.
Missouri voted for the Democratic candidate, Andrew Jackson, over the National Republican candidate, John Quincy Adams. Jackson won Missouri by a margin of 41.28%.
Results
United States presidential election in Alabama, 1828[1] | |||||
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Party | Candidate | Votes | Percentage | Electoral votes | |
Democratic | Andrew Jackson | 8,232 | 70.64% | 3 | |
National Republican | John Quincy Adams | 3,422 | 29.36% | 0 | |
Totals | 11,654 | 100.0% | 3 | ||
References
- ↑ "1828 Presidential General Election Results - Alabama". U.S. Election Atlas. Retrieved 28 February 2013.
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