United States presidential election in Nevada, 1996
Main article: United States presidential election, 1996
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County Results
Clinton—<50%
Dole—<50%
Dole—50-60% | |||||||||||||||||||||||||||||||||||||||||||
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Elections in Nevada |
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None of These Candidates |
The 1996 United States presidential election in Nevada took place on November 5, 1996, as part of the 1996 United States presidential election. Voters chose four representatives, or electors to the Electoral College, who voted for President and Vice President.
A swing state, Nevada was narrowly won by incumbent Democratic President Bill Clinton. Clinton took a 43.93% plurality of the popular vote over Republican challenger Bob Dole, who took 42.91%, a victory margin of 1.02%. Reform Party candidate Ross Perot finished in third with 9.47% of the popular vote.[1]
Results
United States presidential election in Nevada, 1996 | |||||
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Party | Candidate | Votes | Percentage | Electoral votes | |
Democratic | Bill Clinton (incumbent) | 203,974 | 43.93% | 4 | |
Republican | Bob Dole | 199,244 | 42.91% | 0 | |
Reform | Ross Perot | 43,986 | 9.47% | 0 | |
N/A | None of these Candidates | 5,608 | 1.21% | 0 | |
Green | Ralph Nader | 4,730 | 1.02% | 0 | |
Libertarian | Harry Browne | 4,460 | 0.96% | 0 | |
Ind. American | Howard Phillips | 1,732 | 0.37% | 0 | |
Natural Law | John Hagelin | 545 | 0.12% | 0 | |
Totals | 464,279 | 100.0% | 4 |
References
- ↑ "1996 Presidential General Election Results". U.S. Election Atlas. Retrieved 30 January 2013.
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