United States presidential election in Wisconsin, 1996

United States presidential election in Wisconsin, 1996

November 5, 1996

Nominee Bill Clinton Bob Dole Ross Perot Party Democratic Republican Reform Home state Arkansas Kansas Texas Running mate Al Gore Jack Kemp Patrick Choate Electoral vote 11 0 0 Popular vote 1,071,971 845,029 227,339 Percentage 48.81% 38.48% 10.35%

County Results   Clinton—80-90%   Clinton—60-70%   Clinton—50-60%   Dole—40-50%   Dole—50-60%

President before election Bill Clinton Democratic Elected President Bill Clinton Democratic

Elections in Wisconsin
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The 1996 United States presidential election in Wisconsin took place on November 5, 1996 as part of the 1996 United States presidential election. Voters chose 11 representatives, or electors to the Electoral College, who voted for President and Vice President.

Wisconsin was won by President Bill Clinton (D) over Senator Bob Dole (R-KS), with Clinton winning 48.81% to 38.48% by a margin of 10.33%. Billionaire businessman Ross Perot (Reform Party of the United States of America-TX) finished in third with 10.35% of the popular vote.^[1]

Results

References

1. ↑ Dave Leip's Atlas of United States Presidential Election Results - 1996 Wisconsin Results

See also

State Results of the 1996 United States presidential election
Candidates	Bill Clinton Bob Dole Ralph Nader Ross Perot Lyndon LaRouche Full list
General articles	Election timeline Democratic primaries Republican primaries Republican Convention Democratic Convention Debates
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Other 1996 elections	House Senate Gubernatorial